Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

\oint_C \vec{F}\cdot d\vec{r} = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 7 6 ; 1 8 | = 50

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

e^{i\pi} + 1 = 0

8ψ² + 7ψ + 0 = 0

448K

∇²ω = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

459K

∂y/∂n = 5y

406K

\lim_{r\to 0} \frac{\sin r}{r} = 1

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

e^{i\pi} + 1 = 0

359K