Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:18Z

11n² + 5n + 4 = 0

F = ma

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dx [x^3] = 3x^2

459K

8ψ² + 7ψ + 0 = 0

406K

∫₀^∞ e^(-α²) dα = √π / 2

181K

∑_{k=1}^{n} k = n(n+1)/2

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