Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:39Z

10y² + 2y + 6 = 0

d/dx [x^3] = 3x^2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 7 4 ; 4 8 | = 40

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

5φ² + 1φ + 1 = 0

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

5z² + 8z + 3 = 0

459K

∫₀^∞ e^(-t²) dt = √π / 2

406K

λ = h/p

1θ² + 2θ + 6 = 0

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

d/dγ [γ^3] = 3γ^2