Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:31Z

11n² + 5n + 4 = 0

E = mc²

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N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

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iħ ∂ψ/∂t = Ĥψ

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4φ² + 6φ + 2 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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F = G m₁m₂ / r²

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∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 7 4 ; 4 8 | = 40

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