Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:53Z

CH₄ + 2O₂ → CO₂ + 2H₂O

∇ × E = −∂B/∂t

460K

det| 3 7 ; 2 4 | = -2

438K

det| 1 1 ; 4 2 | = -2

4γ² + 1γ + 7 = 0

186K

det| 7 4 ; 4 8 | = 40

411K

CaCO₃ → CaO + CO₂

F = G m₁m₂ / r²

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

det| 8 4 ; 2 9 | = 64

det| 10 2 ; 3 11 | = 104

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

4n² + 8n + 6 = 0

∇²t = 0

181K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

80K

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2