Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:19Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∇ × E = −∂B/∂t

438K

d/dβ [β^11] = 11β^10

λ = h/p

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N₂ + 3H₂ ⇌ 2NH₃

411K

3x² + 4x + 6 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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CH₄ + 2O₂ → CO₂ + 2H₂O

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CaCO₃ → CaO + CO₂

\lim_{t\to 0} \frac{\sin t}{t} = 1

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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ω = 2πf

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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F = G m₁m₂ / r²

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