Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:42Z

∑_{k=1}^{n} k = n(n+1)/2

det| 5 6 ; 2 6 | = 18

451K

8ψ² + 7ψ + 0 = 0

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det| 8 9 ; 3 9 | = 45

det| 7 9 ; 1 8 | = 47

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det| 3 6 ; 0 4 | = 12

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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det| 2 3 ; 3 3 | = -3

N₂ + 3H₂ ⇌ 2NH₃

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∂ψ/∂β = 3ψ

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∇²ω = 0

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