Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:01Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

9θ² + 7θ + 4 = 0

186K

\lim_{β\to 0} \frac{\sin β}{β} = 1

411K

4φ² + 6φ + 2 = 0

det| 12 2 ; 2 13 | = 152

448K

1n² + 7n + 3 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

d/dt [t^3] = 3t^2

181K

d/dx [x^9] = 9x^8

80K

F = G m₁m₂ / r²

359K

8ψ² + 7ψ + 0 = 0

455K