Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
333K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
160K
11γ² + 3γ + 6 = 0
det| 9 4 ; 1 10 | = 86
413K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∑_{k=1}^{n} k = n(n+1)/2
297K
det| 6 1 ; 3 7 | = 39
e^{i\pi} + 1 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2