Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

∇²t = 0

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-t²) dt = √π / 2

∂γ/∂θ = 2γ

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

det| 7 9 ; 1 8 | = 47

448K

∂ψ/∂β = 3ψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∂y/∂γ = 8y

459K

\lim_{α\to 0} \frac{\sin α}{α} = 1

406K

λ = h/p

N₂ + 3H₂ ⇌ 2NH₃

181K

8ψ² + 7ψ + 0 = 0

80K

9α² + 7α + 5 = 0

359K

∇ × E = −∂B/∂t

455K