Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z

11n² + 5n + 4 = 0

PV = nRT

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

d/dt [t^3] = 3t^2

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

det| 5 6 ; 2 6 | = 18

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

det| 9 4 ; 1 10 | = 86

406K

PV = nRT

181K

iħ ∂ψ/∂t = Ĥψ

80K

\lim_{α\to 0} \frac{\sin α}{α} = 1

359K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

455K