Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:21Z

∑_{k=1}^{n} k = n(n+1)/2

E = mc²

451K

det| 9 4 ; 1 10 | = 86

264K

det| 8 9 ; 3 9 | = 45

det| 3 6 ; 0 4 | = 12

297K

det| 4 2 ; 6 5 | = 8

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

10ω² + 7ω + 4 = 0

48K

det| 9 8 ; 3 10 | = 66

411K

det| 2 3 ; 3 3 | = -3

∑_{k=1}^{n} k = n(n+1)/2

377K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

299K

d/dt [t^3] = 3t^2

401K