Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:32Z

d/dy [y^8] = 8y^7

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-z²) dz = √π / 2

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\lim_{x\to 0} \frac{\sin x}{x} = 1

iħ ∂ψ/∂t = Ĥψ

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8ψ² + 7ψ + 0 = 0

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d/dn [n^3] = 3n^2

det| 7 6 ; 1 8 | = 50

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e^{i\pi} + 1 = 0

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6t² + 4t + 0 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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10ψ² + 5ψ + 0 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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PV = nRT

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