Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:41Z

∑_{k=1}^{n} k = n(n+1)/2

N₂ + 3H₂ ⇌ 2NH₃

460K

F = ma

438K

4y² + 7y + 7 = 0

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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∇²t = 0

det| 12 6 ; 0 13 | = 156

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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6β² + 2β + 2 = 0

12γ² + 9γ + 1 = 0

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\lim_{r\to 0} \frac{\sin r}{r} = 1

406K

2φ² + 2φ + 5 = 0

det| 7 4 ; 4 8 | = 40

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12n² + 2n + 2 = 0

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N₂ + 3H₂ ⇌ 2NH₃

359K

8x² + 2x + 7 = 0

455K