Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:16Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
451K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
264K
11ψ² + 2ψ + 6 = 0
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
48K
\frac{9}{7} \sum_{i=1}^{n} i^{2}
\frac{2}{8} \sum_{i=1}^{n} i^{2}
8y² + 6y + 2 = 0
\frac{10}{3} \sum_{i=1}^{n} i^{2}
det| 12 5 ; 1 13 | = 151
d/dt [t^4] = 4t^3