Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:04Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

451K

∑_{k=1}^{n} k = n(n+1)/2

264K

det| 8 9 ; 3 9 | = 45

det| 9 4 ; 1 10 | = 86

297K

PV = nRT

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

d/dt [t^3] = 3t^2

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∇²γ = 0

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4t² + 3t + 3 = 0

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9α² + 7α + 5 = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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11t² + 9t + 7 = 0

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ω = 2πf

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