Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:25Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
d/dβ [β^11] = 11β^10
3x² + 4x + 6 = 0
det| 9 4 ; 1 10 | = 86
22K
det| 10 2 ; 3 11 | = 104
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
det| 3 6 ; 0 4 | = 12
181K