Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:02Z

11t² + 8t + 0 = 0

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∂ω/∂β = 7ω

11t² + 9t + 7 = 0

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det| 7 4 ; 4 8 | = 40

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det| 3 3 ; 7 4 | = -9

det| 12 2 ; 2 13 | = 152

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det| 12 1 ; 5 13 | = 151

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PV = nRT

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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