Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

∇ × E = −∂B/∂t

246K

d/dt [t^3] = 3t^2

118K

9ψ² + 4ψ + 2 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

43K

8ψ² + 7ψ + 0 = 0

261K

d/dβ [β^6] = 6β^5

ω = 2πf

424K

det| 9 8 ; 3 10 | = 66

76K

det| 6 1 ; 4 7 | = 38

10ω² + 7ω + 4 = 0

41K

λ = h/p

298K

\frac{6}{5} \sum_{i=1}^{n} i^{2}

E = mc²

447K

iħ ∂ψ/∂t = Ĥψ

297K

11y² + 2y + 6 = 0

det| 10 3 ; 1 11 | = 107

2H₂ + O₂ → 2H₂O