Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:36Z
det| 6 5 ; 4 7 | = 22
∫₀^∞ e^(-r²) dr = √π / 2
460K
det| 7 4 ; 4 8 | = 40
438K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
448K
F = ma
∫₀^∞ e^(-x²) dx = √π / 2
406K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 4 2 ; 6 5 | = 8
455K
1φ² + 4φ + 5 = 0