Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:29Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

451K

8ψ² + 7ψ + 0 = 0

264K

det| 8 9 ; 3 9 | = 45

e^{i\pi} + 1 = 0

297K

det| 3 7 ; 2 4 | = -2

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

E = mc²

48K

∑_{k=1}^{n} k = n(n+1)/2

411K

det| 2 3 ; 3 3 | = -3

e^{i\pi} + 1 = 0

377K

12n² + 2n + 2 = 0

299K

det| 12 1 ; 5 13 | = 151

401K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

420K

d/dt [t^3] = 3t^2

109K

7r² + 8r + 5 = 0

184K