Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:04Z

∑_{k=1}^{n} k = n(n+1)/2

∇²β = 0

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∑_{k=1}^{n} k = n(n+1)/2

264K

det| 8 9 ; 3 9 | = 45

det| 12 1 ; 5 13 | = 151

297K

12γ² + 9γ + 1 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 4 7 ; 2 5 | = 6

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∇ × E = −∂B/∂t

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det| 2 3 ; 3 3 | = -3

\oint_C \vec{F}\cdot d\vec{r} = 0

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det| 9 4 ; 1 10 | = 86

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d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

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∂y/∂γ = 8y

109K