Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:06Z

e^{i\pi} + 1 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

F = ma

λ = h/p

186K

d/dt [t^3] = 3t^2

411K

12θ² + 8θ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

∑_{k=1}^{n} k = n(n+1)/2

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ω = 2πf

6t² + 6t + 4 = 0

459K

6n² + 7n + 6 = 0

406K

det| 9 4 ; 1 10 | = 86

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∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

359K