Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:32Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 11 4 ; 5 12 | = 112

186K

∫₀^∞ e^(-ω²) dω = √π / 2

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

22K

8ψ² + 7ψ + 0 = 0

459K

7r² + 8r + 5 = 0

406K

d/dt [t^3] = 3t^2

181K

F = ma

80K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

359K

iħ ∂ψ/∂t = Ĥψ

455K