Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:31Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

7r² + 8r + 5 = 0

438K

F = ma

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 7 6 ; 1 8 | = 50

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12θ² + 8θ + 3 = 0

det| 9 4 ; 1 10 | = 86

448K

d/dt [t^3] = 3t^2

22K

2n² + 4n + 0 = 0

459K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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