Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

det| 4 2 ; 6 5 | = 8

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

7y² + 9y + 1 = 0

186K

det| 11 9 ; 0 12 | = 132

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

6ω² + 4ω + 4 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

406K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

181K

F = G m₁m₂ / r²

80K

N₂ + 3H₂ ⇌ 2NH₃

359K