Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 21:52Z

ω = 2πf

∇ × E = −∂B/∂t

195K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

262K

6n² + 3n + 5 = 0

det| 4 8 ; 3 5 | = -4

det| 7 4 ; 4 8 | = 40

244K

∑_{k=1}^{n} k = n(n+1)/2

F = G m₁m₂ / r²

231K

N₂ + 3H₂ ⇌ 2NH₃

26K

\frac{11}{8} \sum_{i=1}^{n} i^{2}

F = ma

209K

10ω² + 7ω + 4 = 0

331K

8β² + 4β + 5 = 0

iħ ∂ψ/∂t = Ĥψ

163K

6n² + 7n + 6 = 0

28K

3ω² + 4ω + 7 = 0

det| 12 1 ; 0 13 | = 156

PV = nRT

2H₂ + O₂ → 2H₂O