Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

273K

11z² + 3z + 4 = 0

263K

e^{i\pi} + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

139K

ω = 2πf

108K

2H₂ + O₂ → 2H₂O

\frac{12}{6} \sum_{i=1}^{n} i^{2}

333K

d/dt [t^3] = 3t^2

160K

det| 4 8 ; 0 5 | = 20

5z² + 8z + 3 = 0

439K

det| 3 7 ; 2 4 | = -2

413K

det| 4 7 ; 7 5 | = -29

8ψ² + 7ψ + 0 = 0

297K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

128K

10t² + 5t + 2 = 0