Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:41Z

∑_{k=1}^{n} k = n(n+1)/2

6t² + 6t + 4 = 0

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det| 5 2 ; 3 6 | = 24

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4y² + 7y + 7 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

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11t² + 9t + 7 = 0

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∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

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d/dt [t^3] = 3t^2

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6β² + 2β + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

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det| 12 2 ; 2 13 | = 152

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2φ² + 2φ + 5 = 0

ω = 2πf

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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det| 9 4 ; 1 10 | = 86

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