Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:08Z

10y² + 2y + 6 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

6t² + 6t + 4 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

\lim_{β\to 0} \frac{\sin β}{β} = 1

186K

∇ × E = −∂B/∂t

411K

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

459K

8ψ² + 7ψ + 0 = 0

406K

9ψ² + 7ψ + 3 = 0

181K

d/dt [t^3] = 3t^2

80K

det| 8 9 ; 4 9 | = 36

359K