Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∫₀^∞ e^(-θ²) dθ = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 9 4 ; 1 10 | = 86

411K

4φ² + 6φ + 2 = 0

e^{i\pi} + 1 = 0

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 3 7 ; 2 4 | = -2

459K

9α² + 7α + 5 = 0

406K

10t² + 9t + 5 = 0

181K