Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:32Z
det| 6 5 ; 4 7 | = 22
\frac{4}{9} \sum_{i=1}^{n} i^{2}
438K
∇²φ = 0
det| 7 4 ; 4 8 | = 40
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
448K
F = ma
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\lim_{t\to 0} \frac{\sin t}{t} = 1
455K
1φ² + 4φ + 5 = 0