Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:11Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

\oint_C \vec{F}\cdot d\vec{r} = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

PV = nRT

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

8ψ² + 7ψ + 0 = 0

448K

ω = 2πf

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

459K

iħ ∂ψ/∂t = Ĥψ

406K

∂y/∂γ = 8y

181K

det| 11 4 ; 5 12 | = 112

80K

8x² + 2x + 7 = 0

359K