Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:03Z

e^{i\pi} + 1 = 0

6r² + 3r + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

F = ma

det| 7 4 ; 4 8 | = 40

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N₂ + 3H₂ ⇌ 2NH₃

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12θ² + 8θ + 3 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

448K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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e^{i\pi} + 1 = 0

406K