Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:53Z

10γ² + 4γ + 3 = 0

E = mc²

460K

∇ × E = −∂B/∂t

438K

d/dβ [β^11] = 11β^10

\oint_C \vec{F}\cdot d\vec{r} = 0

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

3x² + 4x + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

CH₄ + 2O₂ → CO₂ + 2H₂O

22K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

d/dt [t^3] = 3t^2

181K