Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:26Z

3n² + 7n + 7 = 0

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-ω²) dω = √π / 2

10γ² + 8γ + 7 = 0

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d/dt [t^3] = 3t^2

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\frac{10}{6} \sum_{i=1}^{n} i^{2}

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²ω = 0

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d/dr [r^12] = 12r^11

\lim_{r\to 0} \frac{\sin r}{r} = 1

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10ψ² + 5ψ + 0 = 0

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det| 9 4 ; 1 10 | = 86

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∂z/∂φ = 7z

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∑_{k=1}^{n} k = n(n+1)/2

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