Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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9ψ² + 4ψ + 2 = 0

det| 7 4 ; 4 8 | = 40

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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d/dβ [β^6] = 6β^5

∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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d/dφ [φ^1] = 1φ^0

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