Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

det| 9 5 ; 1 10 | = 85

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

10t² + 9t + 5 = 0

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

459K

F = G m₁m₂ / r²

406K

iħ ∂ψ/∂t = Ĥψ

181K

10ω² + 7ω + 4 = 0

80K