Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-21 09:18Z
∫₀^∞ e^(-z²) dz = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
262K
10ω² + 8ω + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
2K
2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
26K
9r² + 6r + 7 = 0
12θ² + 8θ + 7 = 0
10r² + 5r + 3 = 0
12γ² + 9γ + 7 = 0
5φ² + 3φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂