Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:14Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
264K
11ψ² + 2ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
297K
det| 9 4 ; 1 10 | = 86
252K
λ = h/p
det| 5 6 ; 2 6 | = 18
411K
∑_{k=1}^{n} k = n(n+1)/2
377K