Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:17Z

∑_{k=1}^{n} k = n(n+1)/2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

∇ × E = −∂B/∂t

438K

4y² + 7y + 7 = 0

det| 4 2 ; 5 5 | = 10

186K

∂γ/∂θ = 2γ

411K

∇²t = 0

F = G m₁m₂ / r²

448K

8x² + 2x + 7 = 0

22K

6β² + 2β + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

2φ² + 2φ + 5 = 0

ΔS ≥ 0

181K

5α² + 7α + 6 = 0

\lim_{n\to 0} \frac{\sin n}{n} = 1

det| 7 8 ; 0 8 | = 56