Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:50Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-r²) dr = √π / 2

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 12 1 ; 5 13 | = 151

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

F = G m₁m₂ / r²

459K

\lim_{β\to 0} \frac{\sin β}{β} = 1

406K

∇²ω = 0

∫₀^∞ e^(-ω²) dω = √π / 2

181K

11φ² + 4φ + 0 = 0

80K

d/dr [r^2] = 2r^1

det| 9 4 ; 1 10 | = 86

359K

\lim_{α\to 0} \frac{\sin α}{α} = 1

455K

8β² + 5β + 0 = 0