Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:02Z

11n² + 5n + 4 = 0

det| 9 5 ; 1 10 | = 85

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

12γ² + 9γ + 1 = 0

448K

2n² + 4n + 0 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

2H₂ + O₂ → 2H₂O

459K

det| 5 2 ; 3 6 | = 24

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

e^{i\pi} + 1 = 0

80K

8ψ² + 7ψ + 0 = 0

359K