Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:37Z

11n² + 5n + 4 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

ω = 2πf

411K

4φ² + 6φ + 2 = 0

ΔS ≥ 0

448K

λ = h/p

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∂γ/∂θ = 2γ

459K

det| 1 4 ; 3 2 | = -10

406K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

181K

8ψ² + 7ψ + 0 = 0

80K

e^{i\pi} + 1 = 0

359K

∇²r = 0

455K