Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:28Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

det| 9 4 ; 1 10 | = 86

438K

∫₀^∞ e^(-x²) dx = √π / 2

PV = nRT

186K

ω = 2πf

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

10γ² + 8γ + 7 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

11φ² + 4φ + 0 = 0

80K