Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:31Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

∂ω/∂β = 7ω

PV = nRT

186K

det| 9 4 ; 1 10 | = 86

411K

det| 3 3 ; 7 4 | = -9

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

PV = nRT

det| 10 2 ; 3 11 | = 104

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

ΔS ≥ 0

181K

CH₄ + 2O₂ → CO₂ + 2H₂O

80K

det| 11 5 ; 0 12 | = 132

359K