Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:51Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

10ψ² + 5ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

6t² + 6t + 4 = 0

459K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1