Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:42Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-z²) dz = √π / 2
438K
4y² + 7y + 7 = 0
∇²t = 0
det| 7 6 ; 1 8 | = 50
448K
6β² + 2β + 2 = 0
det| 4 8 ; 3 5 | = -4
459K
det| 9 4 ; 1 10 | = 86
406K
∑_{k=1}^{n} k = n(n+1)/2
181K
CH₄ + 2O₂ → CO₂ + 2H₂O
455K