Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:08Z

11n² + 5n + 4 = 0

det| 3 1 ; 7 4 | = 5

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

6t² + 6t + 4 = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 3 7 ; 2 4 | = -2

459K

8ψ² + 7ψ + 0 = 0

406K

det| 3 6 ; 0 4 | = 12

181K

∑_{k=1}^{n} k = n(n+1)/2

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