Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

d/dx [x^9] = 9x^8

186K

6t² + 6t + 4 = 0

411K

4φ² + 6φ + 2 = 0

∂y/∂n = 5y

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∇²ω = 0

N₂ + 3H₂ ⇌ 2NH₃

181K

e^{i\pi} + 1 = 0

80K

d/dr [r^2] = 2r^1

det| 2 3 ; 5 3 | = -9

359K